https://openweathermap.org/weather-conditions
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Call current weather data
https://api.openweathermap.org/data/2.5/weather?lat=39.1958&lon=-95.2083&appid=02937867dce4be1ea755fb1a3378315d&units=imperial
https://api.openweathermap.org/data/2.5/weather?q=McLouth,us&appid=02937867dce4be1ea755fb1a3378315d&units=imperial
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Call 5 day / 3 hour forecast data
https://api.openweathermap.org/data/2.5/forecast?lat=39.1958&lon=-95.2083&appid=02937867dce4be1ea755fb1a3378315d&units=imperial
https://api.openweathermap.org/data/2.5/forecast?q=McLouth,us&appid=02937867dce4be1ea755fb1a3378315d&units=imperial
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callback
api.openweathermap.org/data/2.5/forecast?lat=39.1958&lon=-95.2083&appid=02937867dce4be1ea755fb1a3378315d&units=imperial&callback=test
api.openweathermap.org/data/2.5/forecast?q=McLouth,us&appid=02937867dce4be1ea755fb1a3378315d&units=imperial&callback=test
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cnt optional A number of timestamps, which will be returned in the API response.
https://api.openweathermap.org/data/2.5/forecast?lat=39.1958&lon=-95.2083&appid=02937867dce4be1ea755fb1a3378315d&units=imperial&cnt=3
https://api.openweathermap.org/data/2.5/forecast?q=McLouth,us&appid=02937867dce4be1ea755fb1a3378315d&units=imperial&cnt=3
The cnt parameter gives you the count of data. With this endpoint you get a 5 day forecast with a 3 hour interval per day, which means:
Copy
1 day - cnt = 8
2 days - cnt = 16
3 days - cnt = 24
4 days - cnt = 32
5 days - cnt = 40
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res.json()).subscribe(data => {
this.items = data;
for(var i = 0; i < this.items.list.length; i++){
this.dates = this.items.list[i].dt_txt.substring(10);
this.temps = this.items.list[i].main;
//if 12 o'clock middat is found
arraycontainsMidday = (this.dates.indexOf("12:00:00") > -1);
}
for(var j = 0; j < this.items.list.length; j++){
this.temps = this.items.list[j].main.temp;
}
})
}
-->
